标签：hduj   c++   

So Easy!

　　A sequence S_n is defined as:

Where a, b, n, m are positive integers.┌x┐is the ceil of x. For example, ┌3.14┐=4. You are to calculate S_n.
　　You, a top coder, say: So easy!

2 3 1 2013
2 3 2 2013
2 2 1 2013

4
14
4

#include<iostream>
#include<cstring>
using namespace std;
typedef long long ll;
ll a,b,n,m;

struct matrix {
    ll f[2][2];
};

matrix mul(matrix A,matrix B){
    matrix s;
    memset(s.f,0,sizeof s.f);
    ll i,j,k;
    for(k=0;k<2;k++)
    for(i=0;i<2;i++){
        if(!A.f[i][k])  continue;
        for(j=0;j<2;j++){
            if(!B.f[k][j])   continue;
            s.f[i][j]+=A.f[i][k]*B.f[k][j];
            s.f[i][j]%=m;
        }
    }
    return s;
}

matrix pow_mod(matrix A,ll k){
    matrix s;
    s.f[0][0]=s.f[1][1]=1;
    s.f[0][1]=s.f[1][0]=0;
    while(k){
        if(k&1)  s=mul(s,A);
        A=mul(A,A);
        k>>=1;
    }
    return s;
}

int main(){
    while(cin>>a>>b>>n>>m){
        matrix e;
        ll p=2*a;
        ll q=b-a*a;
        e.f[0][0]=p;e.f[0][1]=1;
        e.f[1][0]=q;e.f[1][1]=0;

        e=pow_mod(e,n-1);
        ll ans=((p*e.f[0][0]+2*e.f[1][0])%m+m)%m;
        cout<<ans<<endl;
    }
    return 0;
}

hdu 4565 So Easy! 矩阵

标签：hduj   c++   

原文地址：http://blog.csdn.net/hyccfy/article/details/41381139