标签:des style blog io color os sp for on
Given a collection of integers that might contain duplicates, S, return all possible subsets.
Note:
For example,
If S = [1,2,2]
, a solution is:
[ [2], [1], [1,2,2], [2,2], [1,2], [] ]
C++代码实现:
#include<iostream> #include<vector> #include<algorithm> using namespace std; class Solution { public: vector<vector<int> > subsetsWithDup(vector<int> &S) { if(S.empty()) return vector<vector<int>>(); sort(S.begin(),S.end()); int n=1<<S.size(); int i=0; vector<vector<int> > ret; while(i<n) { vector<int> temp; int index=0; int j=i; while(j>0) { if(j&1) temp.push_back(S[index]); j=j>>1; index++; } int k; for(k=0;k<(int)ret.size();k++) { if(ret[k]==temp) break; } if(k==(int)ret.size()) ret.push_back(temp); i++; } return ret; } }; int main() { Solution s; vector<int> vec= {2,1,2}; vector<vector<int> > result=s.subsetsWithDup(vec); for(auto a:result) { for(auto v:a) cout<<v<<" "; cout<<endl; } }
标签:des style blog io color os sp for on
原文地址:http://www.cnblogs.com/wuchanming/p/4116309.html