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Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
C++代码实现:
#include<iostream> #include<new> #include<vector> #include<cmath> using namespace std; //Definition for singly-linked list. struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; //Definition for binary tree struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: TreeNode *sortedListToBST(ListNode *head) { if(head==NULL) return NULL; TreeNode *root=NULL; if(head->next==NULL) { root=new TreeNode(head->val); return root; } ListNode *p=head; ListNode *q=head; ListNode *pre=head; while(q&&q->next) { q=q->next->next; pre=p; p=p->next; } pre->next=NULL; q=p->next; p->next=NULL; root=new TreeNode(p->val); root->left=sortedListToBST(head); root->right=sortedListToBST(q); return root; } int maxDepth(TreeNode *root) { if(root) { if(root->left==NULL&&root->right==NULL) return 1; int leftDepth=maxDepth(root->left); int rightDepth=maxDepth(root->right); return leftDepth>= rightDepth ?(leftDepth+1):(rightDepth+1); } return 0; } void inorder(TreeNode *root) { if(root) { inorder(root->left); cout<<root->val<<" "; inorder(root->right); } } void createList(ListNode *&head) { ListNode *p=NULL; int i=0; int arr[10]= {9,8,5,4,4,3,3,3,2,1}; for(i=0; i<10; i++) { if(head==NULL) { head=new ListNode(arr[i]); if(head==NULL) return; } else { p=new ListNode(arr[i]); p->next=head; head=p; } } } }; int main() { Solution s; TreeNode *root=NULL; ListNode *L=NULL; s.createList(L); root=s.sortedListToBST(L); s.inorder(root); cout<<endl; cout<<s.maxDepth(root)<<endl; }
运行结果:
Convert Sorted List to Binary Search Tree
标签:style blog http io ar color os sp for
原文地址:http://www.cnblogs.com/wuchanming/p/4116567.html