标签:io ar os sp java for strong on bs
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama"
is a palindrome.
"race a car"
is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
简单题,输入一个字符串,不考虑数字、字母以外的任何符号。
判断是否是回文串输出即可。
设置双指针查询即可。
public class Solution { public boolean isPalindrome(String s) { s=s.toLowerCase(); int len = s.length() -1; if(len==-1) return true; for(int i=0,j=len;i<=j;i++,j--){ for(;!((s.charAt(i)>='0'&&s.charAt(i)<='9')||(s.charAt(i)>='a'&&s.charAt(i)<='z'))&&i<j;i++); for(;!((s.charAt(j)>='0'&&s.charAt(j)<='9')||(s.charAt(j)>='a'&&s.charAt(j)<='z'))&&i<j;j--); if(s.charAt(i)!=s.charAt(j)) return false; } return true; } }
标签:io ar os sp java for strong on bs
原文地址:http://blog.csdn.net/zhuangjingyang/article/details/41427957