码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode:Evaluate Reverse Polish Notation

时间:2014-11-25 10:53:22      阅读:250      评论:0      收藏:0      [点我收藏+]

标签:leetcode   algorithm   

题目描述:

Evaluate the value of an arithmetic expression in Reverse Polish Notation.

Valid operators are +-*/. Each operand may be an integer or another expression.

Some examples:

  ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
  ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6

思路:遍历逆波兰式的每一项。如果是数字的话,则入栈。如果是运算符,则让栈顶的两个元素出栈,做相应的运算后,将运算的结果入栈。遍历结束后,栈中剩余的元素即为逆波兰式的运算结果。


代码:

int evalRPN(vector<string> &tokens)
{
    int length = tokens.size();
    stack<int> num_stack;
    for(int i = 0;i < length;i++)
    {
        if(strcmp(tokens[i].c_str(),"*") == 0)
        {
            int number1 = num_stack.top();
            num_stack.pop();
            int number2 = num_stack.top();
            num_stack.pop();
            int result = number1 * number2;
            num_stack.push(result);
        }
        else if(strcmp(tokens[i].c_str(),"/") == 0)
        {
            int number1 = num_stack.top();
            num_stack.pop();
            int number2 = num_stack.top();
            num_stack.pop();
            int result = number1 / number2;
            num_stack.push(result);
        }
        else if(strcmp(tokens[i].c_str(),"+") == 0)
        {
            int number1 = num_stack.top();
            num_stack.pop();
            int number2 = num_stack.top();
            num_stack.pop();
            int result = number1 + number2;
            num_stack.push(result);
        }
        else if(strcmp(tokens[i].c_str(),"-") == 0)
        {
            int number1 = num_stack.top();
            num_stack.pop();
            int number2 = num_stack.top();
            num_stack.pop();
            int result = number1 - number2;
            num_stack.push(result);
        }
        else
        {
            int num = atoi(tokens[i].c_str());
            num_stack.push(num);
        }
    }
    return num_stack.top();
}


LeetCode:Evaluate Reverse Polish Notation

标签:leetcode   algorithm   

原文地址:http://blog.csdn.net/yao_wust/article/details/41477111

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!