标签:dp
简单的DP
4 1 4 2 0 0
1 3Hint4 1 : A->B->C->D 4 2 : A->B->C->D, A->C->D, A->B->D
#include <stdio.h> #include <stdlib.h> #include <malloc.h> #include <limits.h> #include <ctype.h> #include <string.h> #include <string> #include <math.h> #include <queue> #include <stack> #include <algorithm> #include <iostream> #include <deque> #include <vector> #include <set> #include <map> using namespace std; #define MAXN 35 int dp[MAXN]; int main(){ int n,m; int i,j; while(~scanf("%d%d",&n,&m)){ if(n==0 && m==0){ break; } memset(dp,0,sizeof(dp)); dp[1] = 1; for(i=1;i<=n;i++){ for(j=1;j<=m;j++){ if((i+j)<=n){ dp[i+j] = dp[i+j]+dp[i]; } } } printf("%d\n",dp[n]); } return 0; }
标签:dp
原文地址:http://blog.csdn.net/zcr_7/article/details/41551063