poj 2538 WERTYU

标签：c++   算法   poj   zoj   编程   

Description

 
A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.

Input

Output

Sample Input

O S, GOMR YPFSU/

Sample Output

I AM FINE TODAY.

水题。。。

#include <iostream>
#include <string.h>
using namespace std;
int main(){
	char ss[10000],s;
	while (gets(ss)){
		int len=strlen(ss),i=0;
		while (i<len){
			s=ss[i++];
			if (s=='W')	cout<<'Q';
			else if (s=='E')	cout<<'W';
			else if (s=='R')	cout<<'E';
			else if (s=='T')	cout<<'R';
			else if (s=='Y')	cout<<'T';
			else if (s=='U')	cout<<'Y';
			else if (s=='I')	cout<<'U';
			else if (s=='O')	cout<<'I';
			else if (s=='P')	cout<<'O';
			else if (s=='[')	cout<<'P';
			else if (s==']')	cout<<'[';
			else if (s=='\\')	cout<<']';
			
			else if (s=='S')	cout<<'A';
			else if (s=='D')	cout<<'S';
			else if (s=='F')	cout<<'D';
			else if (s=='G')	cout<<'F';
			else if (s=='H')	cout<<'G';
			else if (s=='J')	cout<<'H';
			else if (s=='K')	cout<<'J';
			else if (s=='L')	cout<<'K';
			else if (s==';')	cout<<'L';
			else if(s=='\'')	cout<<';';

			else if (s=='X')	cout<<'Z';
			else if (s=='C')	cout<<'X';
			else if (s=='V')	cout<<'C';
			else if (s=='B')	cout<<'V';
			else if (s=='N')	cout<<'B';
			else if (s=='M')	cout<<'N';
			else if (s==',')	cout<<'M';
			else if (s=='.')	cout<<',';
			else if (s=='/')	cout<<'.';

			else if (s=='2')	cout<<'1';
			else if (s=='3')	cout<<'2';
			else if (s=='4')	cout<<'3';
			else if (s=='5')	cout<<'4';
			else if (s=='6')	cout<<'5';
			else if (s=='7')	cout<<'6';
			else if (s=='8')	cout<<'7';
			else if (s=='9')	cout<<'8';
			else if (s=='0')	cout<<'9';
			else if (s=='-')	cout<<'0';
			else if (s=='=')	cout<<'-';

			else
				cout<<s;
		}
		cout<<endl;
		//cin.getline(ss,10000);
	}
	return 0;
}

poj 2538 WERTYU

标签：c++   算法   poj   zoj   编程   

原文地址：http://blog.csdn.net/codeforcer/article/details/41550617