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Leetcode-Two Sum

时间:2014-11-28 06:15:51      阅读:215      评论:0      收藏:0      [点我收藏+]

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Given an array of integers, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2

Have you met this question in a real interview?
 
Analysis:
Be carefull: the return indexs are not zero-based! Means that the position 0 should return 1.
 
Solution:
 1 public class Solution {
 2     public int[] twoSum(int[] numbers, int target) {
 3         int[] res = new int[2];
 4         Map<Integer,Integer> map = new HashMap<Integer,Integer>();
 5         for (int i=0;i<numbers.length;i++)
 6             if (map.containsKey(target-numbers[i])){
 7                 res[0] = map.get(target-numbers[i]);
 8                 res[1] = i+1;
 9                 break;
10             } else {
11                 map.put(numbers[i],i+1);
12             }
13 
14         return res;
15     }
16 }

 

Leetcode-Two Sum

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原文地址:http://www.cnblogs.com/lishiblog/p/4127589.html

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