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Leetcode-Climbing Stairs

时间:2014-11-29 07:04:53      阅读:187      评论:0      收藏:0      [点我收藏+]

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You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

Analysis:

d[i] = d[i-1]+d[i-2]. i steps is the way of reaching i-1 steps + the way of reaching i-2 steps.

Solution:

 1 public class Solution {
 2     public int climbStairs(int n) {
 3         if (n==0) return 0;
 4         if (n==1) return 1;
 5         if (n==2) return 2;
 6     
 7         int first = 1;
 8         int second = 2;
 9         for (int i=3;i<=n;i++){
10             int newVal = first+second;
11             first=second;
12             second = newVal;
13         }
14 
15         return second;
16         
17     }
18 }

 

Leetcode-Climbing Stairs

标签:style   blog   io   ar   color   sp   for   on   div   

原文地址:http://www.cnblogs.com/lishiblog/p/4129890.html

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