标签:style blog io ar color sp for strong on
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
Solution:
1 public class Solution { 2 public int lengthOfLastWord(String s) { 3 s = s.trim(); 4 int index = s.length()-1; 5 while (index>=0 && s.charAt(index)!=‘ ‘) 6 index--; 7 return (s.length()-index-1); 8 } 9 }
标签:style blog io ar color sp for strong on
原文地址:http://www.cnblogs.com/lishiblog/p/4129900.html