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【LeetCode】Balanced Binary Tree

时间:2014-11-29 17:33:54      阅读:169      评论:0      收藏:0      [点我收藏+]

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Balanced Binary Tree

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

 

递归来做很简单。

一棵树要满足平衡条件必须同时满足以下三个全部条件:

1、左子树满足平衡条件

2、右子树满足平衡条件

3、左右子树深度差不超过1

 

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isBalanced(TreeNode *root) {
        if(root == NULL)
            return true;
        if(isBalanced(root->left) && isBalanced(root->right))
        {
            int left = height(root->left);
            int right = height(root->right);
            if(fabs(left-right) <= 1)
                return true;
            else
                return false;
        }
        else 
            return false;
    }
    int height(TreeNode* root)
    {
        if(root == NULL)
            return 0;
        int left = height(root->left);
        int right = height(root->right);
        return max(left,right)+1;
    }
};

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【LeetCode】Balanced Binary Tree

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原文地址:http://www.cnblogs.com/ganganloveu/p/4131108.html

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