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Convert Sorted Array to Binary Search Tree
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
这题思路参照Convert Sorted List to Binary Search Tree,由于vector可以用下标访问,因此不用设置快慢节点,直接访问中间点。
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode *sortedArrayToBST(vector<int> &num) { if(num.empty()) return NULL; else return Helper(num, 0, num.size()-1); } TreeNode *Helper(vector<int> &num, int begin, int end) { if(begin > end) return NULL; else { int mid = (begin+end)/2; int midV = num[mid]; TreeNode* root = new TreeNode(midV); root->left = Helper(num, begin, mid-1); root->right = Helper(num, mid+1, end); return root; } } };
【LeetCode】Convert Sorted Array to Binary Search Tree
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原文地址:http://www.cnblogs.com/ganganloveu/p/4131727.html