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Linked List Cycle
Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
SOLUTION 1:
经典快慢指针问题。如果存在环,fast, slow必然会相遇。就像2个速度不一样的人在环形跑道赛跑,总有一个时间他们会相遇。
如果fast到达了null,就是没有环,可以返回false.
1 package Algorithms.list; 2 3 import Algorithms.algorithm.others.ListNode; 4 5 /** 6 * Definition for singly-linked list. 7 * class ListNode { 8 * int val; 9 * ListNode next; 10 * ListNode(int x) { 11 * val = x; 12 * next = null; 13 * } 14 * } 15 */ 16 public class HasCycle { 17 public boolean hasCycle(ListNode head) { 18 if (head == null) { 19 return false; 20 } 21 22 ListNode slow = head; 23 ListNode fast = head; 24 25 while (fast != null && fast.next != null) { 26 slow = slow.next; 27 fast = fast.next.next; 28 if (slow == fast) { 29 return true; 30 } 31 } 32 33 return false; 34 } 35 }
LeetCode: Linked List Cycle 解题报告
标签:style blog io color sp for strong on div
原文地址:http://www.cnblogs.com/yuzhangcmu/p/4132213.html