码迷,mamicode.com
首页 > 其他好文 > 详细

a letter and a number

时间:2014-11-30 06:14:14      阅读:184      评论:0      收藏:0      [点我收藏+]

标签:style   blog   ar   color   os   sp   java   for   on   

描述we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 
输入
On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
输出
for each case, you should the result of y+f(x) on a line
样例输入
6
R 1
P 2
G 3
r 1
p 2
g 3
样例输出
19
18
10
-17
-14
-4

 1 import java.util.Scanner;
 2 
 3 public class Main {
 4     public static void main(String[] args) {
 5         Scanner scanner=new Scanner(System.in);
 6         int T;
 7         char s[]=new char[1];
 8         int result;
 9         int number;
10         
11         T=scanner.nextInt();
12         while(true){
13             if(T==0)
14                 break;
15             T--;
16             
17             s=scanner.next().toCharArray();
18             number=scanner.nextInt();
19             
20             if(s[0]>=‘a‘ && s[0]<=‘z‘){
21                 result=-(s[0]-‘a‘+1)+number;
22             }
23             else
24                 result=(s[0]-‘A‘+1)+number;
25             
26             System.out.println(result);    
27         }
28     } 
29 }

 

 

a letter and a number

标签:style   blog   ar   color   os   sp   java   for   on   

原文地址:http://www.cnblogs.com/zqxLonely/p/4132336.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!