颠倒链接表顺序

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用一种算法来颠倒一个单链表的顺序，递归和非递归

#include <iostream>
using namespace std;
struct Node
{
	int data;
	Node *next;		
};
Node* createLinkList(int a[], int n)
{	
	if(a == NULL || n == 0)return NULL;
	Node *L = NULL,*t = NULL;
	for(int i = 0; i < n; i++)
	{
		if( i == 0)
		{
			L = new Node;
			L->data = a[i];
			L->next = NULL;
			t = L;
		}
		else
		{
			Node *s = new Node;
			s->data = a[i];
			s->next = NULL;
			t->next = s;
			t = s;		
		}
	
	}
	return L;				
}
void showLinkList(const Node *L)
{
	if( L == NULL)return;
 	const Node *q = L;
	while(q != NULL)
	{
		cout << q->data << endl;
		q = q->next;
	}
}
Node* reverseLinkList(Node *L)
{
	if( L == NULL)return NULL;
 	if(L->next == NULL)return L;
	Node *p = reverseLinkList(L->next);
	L->next->next = L;
	L->next  = NULL;
	
	return p;
}
Node* noRvseLinkList(Node *L)
{
	if( L == NULL || L->next == NULL)return L;
	Node *p = L, *previous = NULL, *NextNode = NULL;
	while(p->next != NULL)
	{
		NextNode = p->next;		//保存起下一个变量 
		p->next = previous;		//将之前的node放在p->next 
		previous = p;
		p = NextNode;	
	}
	p->next = previous;
	return p;
	//return 
}
int main()
{
	int a[] = {1,2,3,4,5,6};
	Node *L = createLinkList(a,6);
	showLinkList(L);
	cout << "-----------------------"<<endl;
//    L = reverseLinkList(L);
	L = noRvseLinkList(L);
	showLinkList(L);	
	return 0;
} 

颠倒链接表顺序

标签：blog   io   os   sp   for   on   2014   log   as   

原文地址：http://blog.csdn.net/jiangge123456/article/details/41647821