Given an index k, return the kth row of the Pascal‘s triangle.
For example, given k = 3,
Return [1,3,3,1]
.
Note:
Could you optimize your algorithm to use only O(k) extra space?
public class Solution { public List<Integer> getRow(int rowIndex) { List<Integer> list = new ArrayList<>(); for(int i=0;i<rowIndex+1;i++){ for(int j=i-1;j>0;j--){ int element = list.get(j)+list.get(j-1); list.set(j, element); } list.add(1); } return list; } }
[LeetCode]Pascal's Triangle II
原文地址:http://blog.csdn.net/guorudi/article/details/41653793