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[LeetCode]Flatten Binary Tree to Linked List

时间:2014-12-01 22:36:30      阅读:178      评论:0      收藏:0      [点我收藏+]

标签:java   leetcode   

Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1
        /        2   5
      / \        3   4   6

The flattened tree should look like:
   1
         2
             3
                 4
                     5
                         6
参考     戴方勤 (soulmachine@gmail.com)     https://github.com/soulmachine/leetcode

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
   public void flatten(TreeNode root) {
        if(root == null) return;
        flatten(root.left);
        flatten(root.right);
        if(root.left == null) return;
        
        TreeNode p = root.left;
        while(p.right!=null) p = p.right;
        p.right = root.right;
        root.right = root.left;
        root.left = null;
    }
}



[LeetCode]Flatten Binary Tree to Linked List

标签:java   leetcode   

原文地址:http://blog.csdn.net/guorudi/article/details/41651529

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