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hdu 1012 u Calculate e

时间:2014-12-02 13:34:06      阅读:131      评论:0      收藏:0      [点我收藏+]

标签:hdu 1012 u calculate

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 31968    Accepted Submission(s): 14314


Problem Description
A simple mathematical formula for e is

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where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

Sample Output
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
 

Source
 

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#include <stdio.h>
double fun ( int i )
{
    double re = 2.5, to = 6;
    int n;
    for ( n = 3; n <= i; n++ )
    {
        re += 1 / to;
        to *= ( n + 1 );
    }
    return re;
}
int main()
{
    int i;
    printf ( "n e\n" );
    printf ( "- -----------\n" );
    printf ( "0 1\n1 2\n2 2.5\n" );
    for ( i = 3; i <= 9; i++ )
        printf ( "%d %.9lf\n", i, fun ( i ) );
    return 0;
}


hdu 1012 u Calculate e

标签:hdu 1012 u calculate

原文地址:http://blog.csdn.net/acm_baihuzi/article/details/41677307

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