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FAFU 1557

时间:2014-12-02 22:13:28      阅读:225      评论:0      收藏:0      [点我收藏+]

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构建字典序,模拟二叉树建26叉树

 

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 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <stdlib.h>
 4 #include <math.h>
 5 #include <time.h>
 6 #include <ctype.h>
 7 #include <string>
 8 #include <queue>
 9 #include <set>
10 #include <map>
11 #include <stack>
12 #include <vector>
13 #include <algorithm>
14 #include <iostream>
15 #define PI acos( -1.0 )
16 using namespace std;
17 typedef long long ll;
18 
19 const int NO = 1e5 + 5;
20 char ch[NO];
21 int n;
22 struct ND
23 {
24     int win;
25     ND *next[26];
26 };
27 
28 int Solve( ND *tree )
29 {
30     for( int i = 0; i < 26; ++i )
31     {
32         if( tree->next[i] == NULL ) continue;
33         if( Solve( tree->next[i] ) )
34         {
35             tree->win = 0;
36             return 0;
37         }
38     }
39     tree->win = 1;
40     return 1;
41 }
42 
43 int main()
44 {
45     int T;
46     scanf( "%d", &T );
47     while( T-- )
48     {
49         ND *tree;
50         tree = new ND;
51         for( int i = 0; i < 26; ++i )
52             tree->next[i] = NULL;
53         scanf( "%d", &n );
54         for( int i = 0; i < n; ++i )
55         {
56             scanf( "%s", ch );
57             ND *p = tree;
58             int len = strlen( ch );
59             for( int j = 0; j < len; ++j )
60             {
61                 int cur = ch[j] - a;
62                 if( p->next[cur] == NULL )
63                 {
64                     p->next[cur] = new ND;
65                     p = p->next[cur];
66                     p->win = 0;
67                     for( int t = 0; t < 26; ++t )
68                         p->next[t] = NULL;
69                 }
70                 else p = p->next[cur];
71             }
72         }
73         if( !Solve( tree ) ) puts( "First." );
74         else puts( "Second." );
75     }
76     return 0;
77 }
View Code

 

FAFU 1557

标签:style   blog   http   io   ar   color   os   sp   for   

原文地址:http://www.cnblogs.com/ADAN1024225605/p/4138400.html

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