标签:des style blog io ar color sp for on
Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You must do this in-place without altering the nodes‘ values.
For example,
Given {1,2,3,4}
, reorder it to {1,4,2,3}
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: void reorderList(ListNode *head) { ListNode *first = head, *middle = head, *tail = head, *pre_tail; if (head == NULL || head->next == NULL) { return;} pre_tail = middle; // find the middle node while (tail != NULL && tail->next != NULL) { pre_tail = middle; middle = middle->next; if (tail->next->next != NULL) { tail = tail->next->next; } else { tail = tail->next; } } ListNode *prev = NULL, *current = middle, *next=middle->next; while (current != NULL) { current->next = prev; prev = current; current = next; if (next != NULL) { next = next->next; } } ListNode *subHead = prev, *subNext = prev; current = head; while (current != NULL) { next = current->next; current->next = subHead; current = next; if (subHead != NULL) { subNext = subHead->next; subHead->next = next; subHead = subNext; } } } };
标签:des style blog io ar color sp for on
原文地址:http://www.cnblogs.com/code-swan/p/4139645.html