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Follow up for problem "Populating Next Right Pointers in Each Node".
What if the given tree could be any binary tree? Would your previous solution still work?
Note:
For example,
Given the following binary tree,
1 / 2 3 / \ 4 5 7
After calling your function, the tree should look like:
1 -> NULL / 2 -> 3 -> NULL / \ 4-> 5 -> 7 -> NULL
/** * Definition for binary tree with next pointer. * struct TreeLinkNode { * int val; * TreeLinkNode *left, *right, *next; * TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {} * }; */ class Solution { public: void connect(TreeLinkNode *root) { TreeLinkNode *head = NULL; //head of the next level TreeLinkNode *prev = NULL; //the leading node on the next level TreeLinkNode *cur = root; //current node of current level while (cur != NULL) { while (cur != NULL) { //iterate on the current level //left child if (cur->left != NULL) { if (prev != NULL) { prev->next = cur->left; } else { head = cur->left; } prev = cur->left; } //right child if (cur->right != NULL) { if (prev != NULL) { prev->next = cur->right; } else { head = cur->right; } prev = cur->right; } //move to next node cur = cur->next; } //move to next level cur = head; head = NULL; prev = NULL; } } };
Populating Next Right Pointers in Each Node II
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原文地址:http://www.cnblogs.com/code-swan/p/4141155.html