标签:style blog io ar color os sp for on
Given a string S and a string T, count the number of distinct subsequences of T in S.
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE"
is a subsequence of "ABCDE"
while "AEC"
is not).
Here is an example:
S = "rabbbit"
, T = "rabbit"
Return 3
.
class Solution { public: int numDistinct(string S, string T) { int m = T.length(); int n = S.length(); if (m > n) return 0; vector<vector<int>> path(m+1, vector<int>(n+1, 0)); for (int k = 0; k <= n; k++) path[0][k] = 1; for (int j = 1; j <= n; j++) { for (int i = 1; i <= m; i++) { path[i][j] = path[i][j-1] + (T[i-1] == S[j-1] ? path[i-1][j-1] : 0); } } return path[m][n]; } };
标签:style blog io ar color os sp for on
原文地址:http://www.cnblogs.com/code-swan/p/4141127.html