标签:dp
题目链接:点击打开链接
裸LCS 注意输入可能有空格
#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <string>
#include <cctype>
#include <vector>
#include <cstdio>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <set>
#define maxn 1005
#define _ll __int64
#define ll long long
#define INF 0x3f3f3f3f
#define Mod 1<<40+10
#define pp pair<int,int>
#define ull unsigned long long
using namespace std;
short dp[maxn][maxn];
char s[maxn],t[maxn];
void solve()
{
memset(dp,0,sizeof(dp));
int lens=strlen(s),lent=strlen(t);
for(int i=1;i<=lens;i++)
for(int j=1;j<=lent;j++)
if(s[i-1]==t[j-1])
dp[i][j]=dp[i-1][j-1]+1;
else
dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
printf("%d\n",dp[lens][lent]);
}
int main()
{
while(gets(s)){
gets(t);
solve();
}
return 0;
}
Uva 10405-Longest Common Subsequence(DP)
标签:dp
原文地址:http://blog.csdn.net/qq_16255321/article/details/41702205