标签:dp
题目链接:点击打开链接
裸LCS 注意输入可能有空格
#include <algorithm> #include <iostream> #include <cstring> #include <cstdlib> #include <string> #include <cctype> #include <vector> #include <cstdio> #include <cmath> #include <queue> #include <stack> #include <map> #include <set> #define maxn 1005 #define _ll __int64 #define ll long long #define INF 0x3f3f3f3f #define Mod 1<<40+10 #define pp pair<int,int> #define ull unsigned long long using namespace std; short dp[maxn][maxn]; char s[maxn],t[maxn]; void solve() { memset(dp,0,sizeof(dp)); int lens=strlen(s),lent=strlen(t); for(int i=1;i<=lens;i++) for(int j=1;j<=lent;j++) if(s[i-1]==t[j-1]) dp[i][j]=dp[i-1][j-1]+1; else dp[i][j]=max(dp[i-1][j],dp[i][j-1]); printf("%d\n",dp[lens][lent]); } int main() { while(gets(s)){ gets(t); solve(); } return 0; }
Uva 10405-Longest Common Subsequence(DP)
标签:dp
原文地址:http://blog.csdn.net/qq_16255321/article/details/41702205