Determine whether an integer is a palindrome. Do this without extra space.
考虑到回文的特点,根据给定数字获得与给定数字低位高位反序的数字。如果是回文数,则两数想等;否则不等。(即使反序数字溢出,也可的到正确结果)
bool isPalindrome(int x) { //C++ int test = 0; int tmp = x; while(tmp>0 ) { test = test*10+tmp%10; tmp = tmp/10; } return (test==x); }
原文地址:http://blog.csdn.net/chenlei0630/article/details/41727807