标签:awk shell.comm diff
1.在B中同时也在A中,comm_a_b.sh
sort -nu A > /tmp/A.txt
sort -nu B > /tmp/B.txt
awk ‘NR==FNR{a[$1]=$2} NR>FNR {if($1 in a){print $0}}‘ /tmp/A.txt /tmp/B.txt > /tmp/result.txt
2.在B中,不在A中,diff_in_b_not_in_a.sh
sort -nu A > /tmp/A.txt
sort -nu B > /tmp/B.txt
awk ‘NR==FNR{a[$1]=$2} NR>FNR {if(!($1 in a)){print $0}}‘ /tmp/A.txt /tmp/B.txt > /tmp/result.txt
标签:awk shell.comm diff
原文地址:http://blog.csdn.net/cleanfield/article/details/41749547