标签:java leetcode depth-first search tree
Given inorder and postorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode buildTree(int[] inorder, int[] postorder) { return buildTree(inorder,postorder,0,inorder.length-1,0,postorder.length-1); } private TreeNode buildTree(int []inorder, int []postorder,int inst,int inend,int postst, int postend){ if(inst>inend||postst>postend||inorder.length<1){ return null; } TreeNode tn =new TreeNode(postorder[postend]); int index = Arrays.binarySearch(inorder, inst, inend+1, postorder[postend]); tn.left = buildTree(inorder,postorder,inst,inst+index-1,postst,postst+index-inst-1); tn.right = buildTree(inorder,postorder,index+1,inend,postst+index-inst,postend-1); return tn; } }
[LeetCode]Construct Binary Tree from Inorder and Postorder Traversal
标签:java leetcode depth-first search tree
原文地址:http://blog.csdn.net/guorudi/article/details/41748431