标签:http io ar os sp for ef amp as
//经典搜索题 #include <iostream> #include <cstring> using namespace std; int primelist[38] = {0,0,1,1,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1}; //素数表, int n; int A[21]; //存放序列结果 int vis[21]; //访问标记 void DFS(int cur) { if(cur == n && primelist[A[n-1]+A[0]]) //结束条件 { cout<<A[0]; for(int i = 1; i < n; ++i) { cout<<" "<<A[i]; } cout<<endl; } else { for(int i = 2; i <= n;++i) { if(!vis[i] && primelist[i + A[cur-1]]) //如果i没有用过并且能与前面的数和成素数 { A[cur] = i; //标记i已访问 vis[i] = 1; //将i加入结果序列 DFS(cur+1); //递归访问 vis[i] = 0; //回溯法标准框架去掉标记 } } } } int main() { int count = 0; A[0] = 1; while(cin>>n) { memset(vis,0,sizeof(vis)); count++; cout<<"Case "<<count<<":"<<endl; DFS(1); cout<<endl; } return 0; }
刘汝佳白书上的题目,回溯法标准框架
自Fenice CSDN
标签:http io ar os sp for ef amp as
原文地址:http://www.cnblogs.com/usedrosee/p/4149699.html