XML解析——DOM

 1 <?xml version="1.0" encoding="GBK"?>
 2 <addresslist>
 3     <linkman>
 4         <name>李兴华</name>
 5         <email>mldnqa@163.com</email>
 6     </linkman>
 7     <linkman>
 8         <name>MLDN</name>
 9         <email>mldnkf@163.com</email>
10     </linkman>
11 </addresslist>

 1 import java.io.* ;
 2 import org.w3c.dom.* ;
 3 import javax.xml.parsers.* ;
 4 public class DOMDemo {
 5     public static void main(String args[]) throws Exception {
 6         // 取得DocumentBuilderFactory类的对象
 7         DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance() ;
 8         // 取得DocumentBuilder类的对象
 9         DocumentBuilder build = factory.newDocumentBuilder()  ;
10         Document doc = build.parse(new File("D:" + File.separator + "dom_demo_01.xml")) ;
11         // 得到所有的linkman节点
12         NodeList nl = doc.getElementsByTagName("linkman") ;
13         for(int x=0;x<nl.getLength();x++){
14             Element e = (Element) nl.item(x) ;    // 取出每一个元素
15             System.out.println("姓名：" + e.getElementsByTagName("name").item(0).getFirstChild().getNodeValue()) ;
16             System.out.println("邮箱：" + e.getElementsByTagName("email").item(0).getFirstChild().getNodeValue()) ;
17         }
18     }
19 }