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Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
给一棵二叉树,判断其是否为平衡二叉树。
使用递归,如果一棵树是平衡二叉树,那么他的左子树和右子树也应该是平衡二叉树,而且两子树的高度差不超过1。depth为该节点的深度初始化为0。
代码如下:
1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 bool isBalanced(TreeNode *root) { 13 // Note: The Solution object is instantiated only once and is reused by each test case. 14 int depth = 0; 15 return isbalance(root, depth); 16 } 17 bool isbalance(TreeNode *root, int &depth) 18 { 19 if(root == NULL) 20 { 21 depth = 0; 22 return true; 23 } 24 int ld,rd; 25 if( isbalance(root->left,ld) && isbalance(root->right,rd)) 26 { 27 if( abs(ld - rd) > 1) 28 { 29 return false; 30 } 31 depth = ld > rd ? ld + 1 : rd + 1; 32 return true; 33 } 34 else return false; 35 } 36 };
[leetcode] Balanced Binary Tree,码迷,mamicode.com
[leetcode] Balanced Binary Tree
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原文地址:http://www.cnblogs.com/jostree/p/3700735.html