标签:java leetcode dynamic programming string
Given a string S and a string T, count the number of distinct subsequences of T in S.
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE"
is
a subsequence of "ABCDE"
while "AEC"
is
not).
Here is an example:
S = "rabbbit"
, T = "rabbit"
Return 3
.
如果S[ i ] == T[ j ] 那么f[i][j] = f[i - 1][j] + f[i - 1][j - 1]
反之f[i][j] = f[i - 1][j]
要注意初始化
public class Solution { public int numDistinct(String S,String T) { if(S.length()<1||T.length()<1||S.length()<T.length()) return 0; int f[][] = new int[S.length()][T.length()]; int in = 0; for(int i=0;i<S.length();i++){ if(S.charAt(i)==T.charAt(0)) in++; f[i][0] = in; } for(int j=1;j<T.length();j++){ for(int i=j;i<S.length();i++){ if(S.charAt(i)==T.charAt(j)){ f[i][j] = f[i-1][j]+f[i-1][j-1]; }else{ f[i][j] = f[i-1][j]; } } } return f[S.length()-1][T.length()-1]; } }
[LeetCode]Distinct Subsequences
标签:java leetcode dynamic programming string
原文地址:http://blog.csdn.net/guorudi/article/details/41810671