标签:depth-first search leetcode
Given a binary tree containing digits from 0-9
only, each root-to-leaf path could represent
a number.
An example is the root-to-leaf path 1->2->3
which represents the number 123
.
Find the total sum of all root-to-leaf numbers.
For example,
1 / 2 3
The root-to-leaf path 1->2
represents the number 12
.
The root-to-leaf path 1->3
represents the number 13
.
Return the sum = 12 + 13 = 25
.
/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { List<String> list = new ArrayList<>(); public int sumNumbers(TreeNode root) { sumNumbers(root,""); int sum = 0; for(String s:list){ sum += Integer.parseInt(s); } return sum; } private void sumNumbers(TreeNode root,String str){ if(root==null) return; String s = str+root.val; if(root.left == null&& root.right == null){ list.add(s); return; } sumNumbers(root.left,s); sumNumbers(root.right,s); } }
[LeetCode]Sum Root to Leaf Numbers
标签:depth-first search leetcode
原文地址:http://blog.csdn.net/guorudi/article/details/41826065