标签:depth-first search leetcode
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent
a number.
An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / 2 3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Return the sum = 12 + 13 = 25.
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
List<String> list = new ArrayList<>();
public int sumNumbers(TreeNode root) {
sumNumbers(root,"");
int sum = 0;
for(String s:list){
sum += Integer.parseInt(s);
}
return sum;
}
private void sumNumbers(TreeNode root,String str){
if(root==null) return;
String s = str+root.val;
if(root.left == null&& root.right == null){
list.add(s);
return;
}
sumNumbers(root.left,s);
sumNumbers(root.right,s);
}
}
[LeetCode]Sum Root to Leaf Numbers
标签:depth-first search leetcode
原文地址:http://blog.csdn.net/guorudi/article/details/41826065