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【Leetcode】Jump Game

时间:2014-05-21 04:39:53      阅读:332      评论:0      收藏:0      [点我收藏+]

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Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

For example:
A = [2,3,1,1,4], return true.

A = [3,2,1,0,4], return false.

bubuko.com,布布扣
 1 class Solution {
 2 public:
 3     bool canJump(int A[], int n) {
 4         int reach = 0;
 5         for (int i = 0; i <= reach && i < n; ++i) {
 6             reach = max(reach, A[i] + i);
 7             if (reach >= n - 1) {
 8                 return true;
 9             }
10         }
11         return reach >= n - 1;
12     }
13 };
View Code

用一个reach变量保存可以达到的最远位置,从前向后扫描不断地扩大reach的范围,若reach可以达到目标位置则返回true.

【Leetcode】Jump Game,布布扣,bubuko.com

【Leetcode】Jump Game

标签:style   blog   class   c   code   tar   

原文地址:http://www.cnblogs.com/dengeven/p/3739485.html

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