4 6 3 *** *B* *B* *H* *H* *** 4 4 **** *BB* *HH* **** 4 4 **** *BH* *HB* **** 5 6 ****** *.BB** *.H*H* *..*.* ******
3 1 2 Sorry , sir , my poor program fails to get an answer.
#include <stdio.h> #include <string.h> #include <queue> #include <algorithm> using namespace std; struct node { int x[2],y[2],step; int b[2],h[2]; }; char map[25][25]; bool vis[25][25][25][25]; int sx[2],sy[2],n,m; int to[4][2] = {0,1,1,0,0,-1,-1,0}; int bfs() { queue<node> Q; node a,next; a.x[0] = sx[0],a.y[0]=sy[0]; a.x[1] = sx[1],a.y[1]=sy[1]; a.step = 0; a.b[0] = a.b[1] = a.h[0] = a.h[1] = 0; Q.push(a); memset(vis,false,sizeof(vis)); while(!Q.empty()) { a = Q.front(); Q.pop(); int i,j; for(i = 0; i<4; i++) { next = a; for(j = 0; j<2; j++) { if(next.b[j]) continue; next.x[j]+=to[i][0]; next.y[j]+=to[i][1]; if(map[next.x[j]][next.y[j]]=='*') { next.x[j]-=to[i][0]; next.y[j]-=to[i][1]; } } if(vis[next.x[0]][next.y[0]][next.x[1]][next.y[1]]) continue; if(next.x[0]==next.x[1]&& next.y[0]==next.y[1] && next.b[0]+next.b[1]==0) continue; next.step++; vis[next.x[0]][next.y[0]][next.x[1]][next.y[1]] = true; int flag = 1; for(j = 0; j<2; j++) { int now = map[next.x[j]][next.y[j]]; if(now<2 && !next.h[now]) { next.h[now]=1; next.b[j] = 1; } if(!next.b[j]) flag = 0; } if(flag) return next.step; Q.push(next); } } return -1; } int main() { int t,i,j; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); int cnt = 0,len = 0; for(i = 0; i<n; i++) { scanf("%s",map[i]); for(j = 0; j<m; j++) { if(map[i][j]=='H') map[i][j] = cnt++; else if(map[i][j]=='B') { sx[len] = i,sy[len] = j; len++; } } } int ans = bfs(); if(ans!=-1) printf("%d\n",ans); else printf("Sorry , sir , my poor program fails to get an answer.\n"); } return 0; }
原文地址:http://blog.csdn.net/libin56842/article/details/41873215