Catalogue: array-分治法搜索
Question
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4
5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
First tryclass Solution {
public:
int findMin(vector<int> &num) {
ret = 0;
binarySearch(num,0,num.size()-1);
return num[ret];
}
void binarySearch(vector<int> &num, int start, int end)
{
if(end-start<=1)
{
if(num[end]>num[start]) return;
else
{
ret = end;
return;
}
}
int mid = (start + end) >> 1;
if(num[start]>num[mid])
binarySearch(num, start, mid);
else if(num[mid+1]>num[end])
binarySearch(num, mid+1, end);
else if(num[mid]>num[mid+1])
ret = mid+1;
}
private:
int ret;
};Result: Accepted
Find Minimum in Rotated Sorted Array
原文地址:http://blog.csdn.net/joannae_hu/article/details/41905283