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Question
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4
5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
First tryclass Solution { public: int findMin(vector<int> &num) { ret = 0; binarySearch(num,0,num.size()-1); return num[ret]; } void binarySearch(vector<int> &num, int start, int end) { if(end-start<=1) { if(num[end]>num[start]) return; else { ret = end; return; } } int mid = (start + end) >> 1; if(num[start]>num[mid]) binarySearch(num, start, mid); else if(num[mid+1]>num[end]) binarySearch(num, mid+1, end); else if(num[mid]>num[mid+1]) ret = mid+1; } private: int ret; };Result: Accepted
Find Minimum in Rotated Sorted Array
原文地址:http://blog.csdn.net/joannae_hu/article/details/41905283