拉丁方阵问题

#include<stdio.h>
#include<stdlib.h>

typedef struct Node
{
	int data;
	struct Node *next;
}Node;
typedef struct Node *LinkList;

//构造一个带有N个结点的循环链表
Node* CreatLists(struct Node *La,int n)
{
	int i;
	struct Node *p,*s;
	La = (LinkList)malloc(sizeof(Node));
	La->next = NULL;
	p = La;
	for(i = 1;i <= n;i++)
	{
		s = (LinkList)malloc(sizeof(Node));
		s->data = i;
		s->next = p->next;
		p->next = s;
		p = p->next;
	}
	p->next = La->next;
	return p->next;
} 

//实现拉丁方阵的输出
void print(struct Node *La,int n)
{
	int i,j;
	struct Node *p,*q;
	p = La;
	for(i = 1;i <= n;i++)
	{
		q = p;
		for(j = 1;j <= n;j++)
		{
			printf("%3d",q->data);
			q = q->next;		
		}
		printf("\n");
		p = p->next;
	}
} 

int main (int argc,char* argv[])
{
	int m;
	struct Node *L,*t;	
	while(1) 
	{
		printf("****************************************************\n");
		printf("*****          ESC键：    退出程序             *****\n");
		printf("*****                                          *****\n");
		printf("*****          其他任意键：打印拉丁方阵        *****\n");
		printf("****************************************************\n");
		if(getch() == 27)
			break;
		else
		{ 
			printf("\n请输入您要打印的拉丁方阵规模（要打印的行数）：\n\n");
			scanf("%d",&m);
			L = CreatLists(L,m);
			printf("\n您输入的规模为%d，打印的方阵如下：\n\n",m);	
			print(L,m);
			printf("\n请输入任意键继续：\n");
			getch();
			system("cls"); 
		} 
	}
	return 0;
}