标签:style blog http io ar color os sp for
1. 二叉树中和为某一值的路径
路径:从树的根节点到叶子节点经过的节点形成的路径,例如途中(10,5,4),(10,5,7),(10,12)
满足和为22的路径有(10,5,7)、(10,12)
参考代码
void FindPath(TreeNode *root, vector<TreeNode> &vec, int cur, int aim) { if (root == NULL) return; vec.push_back(*root); cur += root->val; bool IsLeft = ((root->left == NULL) && (root->right == NULL)); if (cur == aim && IsLeft) { for (vector<TreeNode>::iterator beg = vec.begin(); beg != vec.end(); ++beg) cout << beg->val << " "; cout << endl; } if (root->left != NULL) FindPath(root->left, vec, cur, aim); if (root->right != NULL) FindPath(root->right, vec, cur, aim); vec.pop_back(); } void FindPath(TreeNode *root, int aim) { if (root == NULL) return; vector<TreeNode> vec; FindPath(root, vec, 0, aim); }
测试
#include <iostream> #include <vector> using namespace std; struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int v) : val(v), left(NULL), right(NULL) {}; }; void FindPath(TreeNode *root, vector<TreeNode> &vec, int cur, int aim) { if (root == NULL) return; vec.push_back(*root); cur += root->val; bool IsLeft = ((root->left == NULL) && (root->right == NULL)); if (cur == aim && IsLeft) { for (vector<TreeNode>::iterator beg = vec.begin(); beg != vec.end(); ++beg) cout << beg->val << " "; cout << endl; } if (root->left != NULL) FindPath(root->left, vec, cur, aim); if (root->right != NULL) FindPath(root->right, vec, cur, aim); vec.pop_back(); } void FindPath(TreeNode *root, int aim) { if (root == NULL) return; vector<TreeNode> vec; FindPath(root, vec, 0, aim); } int main() { TreeNode *root = new TreeNode(10); TreeNode *p1 = new TreeNode(5); TreeNode *p2 = new TreeNode(12); TreeNode *p3 = new TreeNode(4); TreeNode *p4 = new TreeNode(7); root->left = p1; root->right = p2; p1->left = p3; p1->right = p4; FindPath(root, 22); }
标签:style blog http io ar color os sp for
原文地址:http://www.cnblogs.com/kaituorensheng/p/4166075.html