标签:style blog io color sp on div log bs
Divide two integers without using multiplication, division and mod operator.
If it is overflow, return MAX_INT.
Solution:
1 public class Solution { 2 public int divide(int dividend, int divisor) { 3 if (divisor==0) return Integer.MAX_VALUE; 4 if (dividend==0) return 0; 5 if (divisor==1) return dividend; 6 if (dividend==Integer.MIN_VALUE && divisor==-1) return Integer.MAX_VALUE; 7 8 boolean neg = false; 9 //change to all negtive number. 10 if (dividend>0){ 11 dividend = -dividend; 12 neg = !neg; 13 } 14 if (divisor>0){ 15 divisor = - divisor; 16 neg = !neg; 17 } 18 19 int minDivisor = Integer.MIN_VALUE >> 1; 20 int cur = divisor; 21 int val = 1; 22 while (cur>=minDivisor && cur>dividend){ 23 cur <<= 1; 24 val <<= 1; 25 } 26 27 int res = 0; 28 while (dividend<=divisor){ 29 while (cur<dividend){ 30 cur >>= 1; 31 val >>= 1; 32 } 33 dividend -= cur; 34 res += val; 35 } 36 37 if (neg) return -res; 38 else return res; 39 } 40 }
标签:style blog io color sp on div log bs
原文地址:http://www.cnblogs.com/lishiblog/p/4166263.html