标签:des blog http ar io color os 使用 sp
Time Limit: 30000/15000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 876 Accepted Submission(s): 329
dp[i][j] 表示前i堆石子构成长度为j的串的方案数;
状态转移方程是:k为i堆使用的数量
dp[i][j] = (dp[i][j] + dp[i-1][j-k] * C[j][k]%M)%M;
自己写挫了,上一大神代码。
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
#define M 1000000007
long long dp[110][10010];
long long C[11000][110];
void cc()
{
int i,j;
C[0][0]=1;
for(i=1;i<10010;i++)
for(j=0;j<=100;j++)
if(j == 0) C[i][j] = C[i-1][j];
else C[i][j] = (C[i-1][j]+C[i-1][j-1])%M;
//C[i][j]=(j==0) ? C[i-1][j] : ();
}
int main()
{
cc();
int n;
int cas = 1;
while(cin >> n)
{
memset(dp,0,sizeof(dp));
dp[0][0] = 1;
int sum = 0;
for(int i = 1;i <= n;i++)
{
int t;
cin >> t;
sum += t;
for(int k = 0;k <= t;k++)
for(int j = k;j <= sum;j++)
dp[i][j] = (dp[i][j] + dp[i-1][j-k] * C[j][k]%M)%M;
}
long long re = 0;
for(int i = 1;i <= sum;i++) re = (re + dp[n][i])%M;
cout << "Case " << cas++<< ": " << re << "\n";
}
return 0;
}
标签:des blog http ar io color os 使用 sp
原文地址:http://www.cnblogs.com/a972290869/p/4166265.html