标签:com http blog style class div img code c java log
这有一个迷宫,有0~8行和0~8列:
1,1,1,1,1,1,1,1,1
1,0,0,1,0,0,1,0,1
1,0,0,1,1,0,0,0,1
1,0,1,0,1,1,0,1,1
1,0,0,0,0,1,0,0,1
1,1,0,1,0,1,0,0,1
1,1,0,1,0,1,0,0,1
1,1,0,1,0,0,0,0,1
1,1,1,1,1,1,1,1,1
0表示道路,1表示墙。
现在输入一个道路的坐标作为起点,再如输入一个道路的坐标作为终点,问最少走几步才能从起点到达终点?
(注:一步是指从一坐标点走到其上下左右相邻坐标点,如:从(3,1)到(4,1)。)
2 3 1 5 7 3 1 6 7
12 11
#include <iostream> #include <vector> #include <cstring> #include <utility> #include <queue> using namespace std; typedef pair<int,int> Point; const int maze[9][9] ={ 1,1,1,1,1,1,1,1,1, 1,0,0,1,0,0,1,0,1, 1,0,0,1,1,0,0,0,1, 1,0,1,0,1,1,0,1,1, 1,0,0,0,0,1,0,0,1, 1,1,0,1,0,1,0,0,1, 1,1,0,1,0,1,0,0,1, 1,1,0,1,0,0,0,0,1, 1,1,1,1,1,1,1,1,1, }; bool visit[9][9]; const int dx[] = {0,1,0,-1}; const int dy[] = {1,0,-1,0}; int bfs(Point startP,Point endP){ queue<Point> p; p.push(startP); visit[startP.first][startP.second] = true; int res = 0,cnt = 0,newCnt = 1; while(!p.empty()){ cnt = newCnt; newCnt = 0; while(cnt--){ Point tmp = p.front(); p.pop(); if(tmp.first == endP.first && tmp.second == endP.second) return res; else{ for(int i = 0; i < 4; ++ i){ int newx = tmp.first + dx[i], newy = tmp.second + dy[i]; if(!visit[newx][newy] && !maze[newx][newy]){ p.push(Point(newx,newy)); visit[newx][newy] = true; newCnt++; } } } } ++res; } return -1; } int main(){ int n; cin >> n; while(n--){ int a,b,c,d; cin >> a >> b >> c >> d; memset(visit,false,sizeof(visit)); cout<<bfs(Point(a,b),Point(c,d))<<endl; } }
标签:com http blog style class div img code c java log
原文地址:http://www.cnblogs.com/xiongqiangcs/p/3700911.html