标签：style blog http ar io color sp for on
Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
题目还是简单的，但是要考虑很多情况。
我写的代码边写边调试，写的比较烂。
1 public class Solution { 2 public int compareVersion(String version1, String version2) { 3 String[] versionsOne=version1.split("\\."); 4 String[] versionsTwo=version2.split("\\."); 5 int oneLength=versionsOne.length; 6 int twoLength=versionsTwo.length; 7 int length=oneLength<twoLength?oneLength:twoLength; 8 9 for (int i = 0; i < length; i++) { 10 while (versionsOne[i].startsWith("0")&&versionsOne[i].length()>1) { 11 versionsOne[i]=versionsOne[i].substring(1); 12 } 13 while (versionsTwo[i].startsWith("0")&&versionsTwo[i].length()>1) { 14 versionsTwo[i]=versionsTwo[i].substring(1); 15 } 16 if (versionsOne[i].length()>versionsTwo[i].length()) { 17 return 1; 18 }else if (versionsOne[i].length()<versionsTwo[i].length()) { 19 return -1; 20 } 21 int l = versionsOne[i].length()<versionsTwo[i].length()?versionsOne[i].length():versionsTwo[i].length(); 22 for (int j = 0; j < l; j++) { 23 int a=versionsOne[i].charAt(j); 24 int b=versionsTwo[i].charAt(j); 25 if (a>b) { 26 return 1; 27 }else if (a<b) { 28 return -1; 29 } 30 } 31 32 } 33 if (oneLength>twoLength) { 34 for (int i = twoLength; i < oneLength; i++) { 35 for (int j = 0; j < versionsOne[i].length(); j++) { 36 if (versionsOne[i].charAt(j)>‘0‘) { 37 return 1; 38 } 39 } 40 } 41 }else if (oneLength<twoLength) { 42 for (int i = oneLength; i < twoLength; i++) { 43 for (int j = 0; j < versionsTwo[i].length(); j++) { 44 if (versionsTwo[i].charAt(j)>‘0‘) { 45 return -1; 46 } 47 } 48 } 49 } 50 return 0; 51 } 52 }
leetcode Compare Version Numbers
标签：style blog http ar io color sp for on
原文地址：http://www.cnblogs.com/birdhack/p/4168180.html
