UVA - 572
Time Limit: 3000MS | Memory Limit: Unknown | 64bit IO Format: %lld & %llu |
Description
Oil Deposits |
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil.
A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.
1 1 * 3 5 *@*@* **@** *@*@* 1 8 @@****@* 5 5 ****@ *@@*@ *@**@ @@@*@ @@**@ 0 0
0 1 2 2
Source
利用DFS,然后递归即可
AC代码:
#include <cstdio> #include <cstring> #include <algorithm> using namespace std; char map[105][105]; int vis[105][105]; void dfs(int i, int j) { if(map[i][j] == '*' || vis[i][j]) return; vis[i][j] = 1; dfs(i-1, j-1); dfs(i-1, j); dfs(i-1, j+1); dfs(i, j-1); dfs(i, j+1); dfs(i+1, j-1); dfs(i+1, j); dfs(i+1, j+1); } int main() { int m, n; while(scanf("%d %d", &m, &n), m || n) { memset(vis, 0, sizeof(vis)); //所有格子都没访问过 for(int i=0; i<105; i++) //初始化图的外沿为‘*’ { for(int j=0; j<105; j++) { map[i][j] = '*'; } } char a[105]; for(int i=1; i<=m; i++) //输入 { scanf("%s", a); for(int j=1; j<=n; j++) { map[i][j] = a[j-1]; } } int count = 0; for(int i=1; i<=m; i++) //DFS的应用 { for(int j=1; j<=n; j++) { if(!vis[i][j] && map[i][j] == '@') { count++; dfs(i, j); } } } printf("%d\n", count); } return 0; }
UVA - 572 - Oil Deposits (图的DFS!)
原文地址:http://blog.csdn.net/u014355480/article/details/41966281