题意 八数码问题
还是八数码问题 只是要输出路径了
#include<cstdio>
#include<cstring>
using namespace std;
const int M = 1000003;
int e[9] = {1, 2, 3, 4, 5, 6, 7, 8, 0};
int x[4] = { -1, 1, 0, 0}, y[4] = {0, 0, -1, 1};
int dir[M], pre[M], h[M], s[M][9];
char pri[5] = "udlr";
int aton(int a[])
{
int t = 0;
for(int i = 0; i < 9; ++i)
t = t * 10 + a[i];
return t;
}
int search_hash(int a[])
{
int t = aton(a), p = t % M;
while(h[p])
{
if(h[p] == t) return p;
++p;
if(p >= M) p = 0;
}
return p;
}
void print(int p)
{
if(pre[p])
{
print(pre[p]);
printf("%c", pri[dir[p]]);
}
}
int bfs()
{
memset(h, 0, sizeof(h));
h[aton(s[1]) % M] = aton(s[1]);
int fro = 1, rear = 2, r, c, k = 0, nr, nc, nk, p;
int t[9], tmp, cur;
while(fro < rear)
{
memcpy(t, s[fro], sizeof(t));
cur = search_hash(t);
if(memcmp(t, e, sizeof(t)) == 0) return cur;
for(k = 0; t[k];) ++k;
r = k / 3, c = k % 3;
for(int i = 0; i < 4; ++i)
{
memcpy(t, s[fro], sizeof(t));
nr = r + x[i], nc = c + y[i], nk = nr * 3 + nc;
if(nr < 0 || nr > 2 || nc < 0 || nc > 2) continue;
tmp = t[nk];
t[nk] = 0;
t[k] = tmp;
p = search_hash(t);
if(h[p] == 0)
{
h[p] = aton(t);
dir[p] = i;
pre[p] = cur;
memcpy(s[rear], t, sizeof(t));
++rear;
}
}
++fro;
}
return 0;
}
int main()
{
char c;
while(~scanf("%d", &s[1][0]))
{
memset(dir, 0, sizeof(dir));
memset(pre, 0, sizeof(pre));
for(int i = 1; i < 9; ++i)
{
scanf(" %c", &c);
if(c == 'x') s[1][i] = 0;
else s[1][i] = c - '0';
}
int ans = bfs();
if(ans) print(ans);
else printf("unsolvable");
printf("\n");
}
return 0;
}
/*
2 3 4 1 5 0 7 6 8
*/
Description
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 x
1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4
5 6 7 8 5 6 7 8 5 6 7 8 5 6 7 8
9 x 10 12 9 10 x 12 9 10 11 12 9 10 11 12
13 14 11 15 13 14 11 15 13 14 x 15 13 14 15 x
r-> d-> r->
Input
1 2 3 x 4 6 7 5 8
1 2 3 x 4 6 7 5 8
Output
Sample Input
2 3 4 1 5 x 7 6 8
Sample Output
ullddrurdllurdruldr
Source
原文地址:http://blog.csdn.net/acvay/article/details/42003855