题意 八数码问题
还是八数码问题 只是要输出路径了
#include<cstdio> #include<cstring> using namespace std; const int M = 1000003; int e[9] = {1, 2, 3, 4, 5, 6, 7, 8, 0}; int x[4] = { -1, 1, 0, 0}, y[4] = {0, 0, -1, 1}; int dir[M], pre[M], h[M], s[M][9]; char pri[5] = "udlr"; int aton(int a[]) { int t = 0; for(int i = 0; i < 9; ++i) t = t * 10 + a[i]; return t; } int search_hash(int a[]) { int t = aton(a), p = t % M; while(h[p]) { if(h[p] == t) return p; ++p; if(p >= M) p = 0; } return p; } void print(int p) { if(pre[p]) { print(pre[p]); printf("%c", pri[dir[p]]); } } int bfs() { memset(h, 0, sizeof(h)); h[aton(s[1]) % M] = aton(s[1]); int fro = 1, rear = 2, r, c, k = 0, nr, nc, nk, p; int t[9], tmp, cur; while(fro < rear) { memcpy(t, s[fro], sizeof(t)); cur = search_hash(t); if(memcmp(t, e, sizeof(t)) == 0) return cur; for(k = 0; t[k];) ++k; r = k / 3, c = k % 3; for(int i = 0; i < 4; ++i) { memcpy(t, s[fro], sizeof(t)); nr = r + x[i], nc = c + y[i], nk = nr * 3 + nc; if(nr < 0 || nr > 2 || nc < 0 || nc > 2) continue; tmp = t[nk]; t[nk] = 0; t[k] = tmp; p = search_hash(t); if(h[p] == 0) { h[p] = aton(t); dir[p] = i; pre[p] = cur; memcpy(s[rear], t, sizeof(t)); ++rear; } } ++fro; } return 0; } int main() { char c; while(~scanf("%d", &s[1][0])) { memset(dir, 0, sizeof(dir)); memset(pre, 0, sizeof(pre)); for(int i = 1; i < 9; ++i) { scanf(" %c", &c); if(c == 'x') s[1][i] = 0; else s[1][i] = c - '0'; } int ans = bfs(); if(ans) print(ans); else printf("unsolvable"); printf("\n"); } return 0; } /* 2 3 4 1 5 0 7 6 8 */
Description
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 x
1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 5 6 7 8 5 6 7 8 5 6 7 8 5 6 7 8 9 x 10 12 9 10 x 12 9 10 11 12 9 10 11 12 13 14 11 15 13 14 11 15 13 14 x 15 13 14 15 x r-> d-> r->
Input
1 2 3 x 4 6 7 5 8
1 2 3 x 4 6 7 5 8
Output
Sample Input
2 3 4 1 5 x 7 6 8
Sample Output
ullddrurdllurdruldr
Source
原文地址:http://blog.csdn.net/acvay/article/details/42003855