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public class Solution { public int atoi(String s) { int MAX=2147483647; int MIN=-2147483648; s = s.trim();//1.去除空格 long value = 0; int flag = 1; for (int i = 0; i < s.length(); i++) { if (i == 0 && (s.charAt(i) == '+' || s.charAt(i) == '-')) {//2.正负号 if (s.charAt(i) == '-') { flag = -1; } continue; } if (s.charAt(i) < '0' || s.charAt(i) > '9') break;//3.遇见0-9以外字符退出循环 value = 10 * value + s.charAt(i) - '0'; long temp=value*flag; if(temp>MAX){value=MAX;break;}else if(temp<MIN){value=MIN;break;}//4.Int溢出中断 } value = value * flag; return (int) value; } }
LeetCode--String to Integer (atoi)
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原文地址:http://blog.csdn.net/wj512416359/article/details/42031773