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...又是TLE,对于单组数据肯定TLE不了,问题是多组的时候就呵呵了...
按height分组去搞,然后判一下是否不属于同一个串...
const maxn=100419; var x,y,rank,sa,c,col,h,rec:array[0..maxn] of longint; pd:array[0..maxn] of boolean; s:ansistring; n,k,maxlen,cnta:longint; function max(x,y:longint):longint; begin if x>y then exit(x) else exit(y); end; function min(x,y:longint):longint; begin if x<y then exit(x) else exit(y); end; procedure swap(var x,y:longint);var tmp:longint; begin tmp:=x;x:=y;y:=tmp; end; procedure make; var i,p,tot:longint; begin p:=1; while p<n do begin fillchar(c,sizeof(c),0); for i:= 1 to n-p do y[i]:=rank[i+p]; for i:= n-p+1 to n do y[i]:=0; for i:= 1 to n do inc(c[y[i]]); for i:= 1 to n do inc(c[i],c[i-1]); for i:= 1 to n do begin sa[c[y[i]]]:=i; dec(c[y[i]]); end; fillchar(c,sizeof(c),0); for i:= 1 to n do x[i]:=rank[i]; for i:= 1 to n do inc(c[x[i]]); for i:= 1 to n do inc(c[i],c[i-1]); for i:= n downto 1 do begin y[sa[i]]:=c[x[sa[i]]]; dec(c[x[sa[i]]]); end; for i:= 1 to n do sa[y[i]]:=i; tot:=1; rank[sa[1]]:=1; for i:= 2 to n do begin if (x[sa[i]]<>x[sa[i-1]]) or (x[sa[i]+p]<>x[sa[i-1]+p]) then inc(tot); rank[sa[i]]:=tot; end; p:=p<<1; end; for i:= 1 to n do sa[rank[i]]:=i; end; procedure makeh; var i,p,j:longint; begin p:=0; h[1]:=0; for i:= 1 to n do begin p:=max(p-1,0); if rank[i]=1 then continue; j:=sa[rank[i]-1]; while (j+p<=n) and (i+p<=n) and (s[i+p]=s[j+p]) do inc(p); h[rank[i]]:=p; end; end; procedure init; var i,j,tot:longint; s1:ansistring; begin k:=n>>1; readln(s); tot:=1; maxlen:=length(s); for i:= 1 to maxlen do col[i]:=1; for i:= 2 to n do begin readln(s1); s:=s+‘#‘; maxlen:=max(length(s1),maxlen); inc(tot); for j:= length(s)+1 to length(s)+length(s1) do col[j]:=tot; s:=s+s1; end; n:=length(s); fillchar(c,sizeof(c),0); for i:= 1 to n do x[i]:=ord(s[i]); for i:= 1 to n do inc(c[x[i]]); for i:= 1 to 128 do inc(c[i],c[i-1]); for i:= 1 to n do begin sa[c[x[i]]]:=i; dec(c[x[i]]); end; tot:=1; rank[sa[1]]:=1; for i:= 2 to n do begin if x[sa[i]]<>x[sa[i-1]] then inc(tot); rank[sa[i]]:=tot; end; make; makeh; end; function check(x:longint):boolean; var i,j,tot,cnt:longint; begin fillchar(pd,sizeof(pd),false); pd[0]:=true; tot:=0; cnt:=0; if not pd[sa[1]] then inc(tot); pd[sa[1]]:=true; for i:= 2 to n do begin if h[i]<x then begin if tot>k then begin inc(cnt); rec[cnt]:=i-1; end; tot:=0; fillchar(pd,sizeof(pd),false); pd[0]:=true; end; if not pd[col[sa[i]]] then inc(tot); pd[col[sa[i]]]:=true; end; if tot>k then begin inc(cnt); rec[cnt]:=i-1; end; if cnt>0 then begin cnta:=cnt; exit(true); end; exit(false); end; procedure qsort(l,r:longint); var i,j,mid,tmp:longint; begin if l>r then exit; i:=l; j:=r; mid:=rec[l+random(r-l+1)]; repeat while rec[i]<mid do inc(i); while rec[j]>mid do dec(j); if i<=j then begin swap(i,j); inc(i); dec(j); end; until i>j; qsort(i,r); qsort(l,j); end; procedure solve; var l,r,mid,tot,ans,i,j:longint; begin l:=1; r:=maxlen; ans:=0; while l<=r do begin mid:=(l+r)>>1; if check(mid) then begin ans:=mid; l:=mid+1; end else r:=mid-1; end; fillchar(pd,sizeof(pd),false); if ans=0 then begin writeln(‘?‘); exit; end; qsort(1,cnta); for i:= 1 to cnta do writeln(copy(s,sa[rec[i]],ans)); end; Begin readln(n); while n<>0 do begin init; solve; writeln; readln(n); end; End.
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原文地址:http://www.cnblogs.com/EC-Ecstasy/p/4175440.html