Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete at most two transactions.
Note:
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
下面为具体的实现 ps:可以同一天买入卖出
public class Solution {
public int maxProfit(int[] prices) {
if(prices.length<2) return 0;
int []left =new int[prices.length];
int []right = new int[prices.length];
int minVal = prices[0];
for(int i=1;i<prices.length;i++){
minVal = Math.min(minVal, prices[i]);
left[i] = Math.max(left[i-1], prices[i]-minVal);
}
int maxVal = prices[prices.length-1];
for(int i=prices.length-2;i>=0;i--){
maxVal = Math.max(maxVal, prices[i]);
right[i] = Math.max(right[i+1], maxVal -prices[i]);
}
int res = left[0]+right[0];
for(int i=1;i<prices.length;i++){
res = Math.max(res, left[i]+right[i]);
}
return res;
}
}
[LeetCode]Best Time to Buy and Sell Stock III
原文地址:http://blog.csdn.net/guorudi/article/details/42043735