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[leetcode]

时间:2014-12-21 22:11:28      阅读:289      评论:0      收藏:0      [点我收藏+]

标签:leetcode   算法   

问题描述:

Given a collection of numbers, return all possible permutations.

For example,
[1,2,3] have the following permutations:
[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2,1].


基本思想:

利用了C++STL的组合数的性质

代码:

#include <algorithm>   //C++
class Solution {
public:
    vector<vector<int> > permute(vector<int> &num) {
        int size = num.size();
        sort(num.begin(),num.end());
        
        vector<vector<int> > result;
        vector<int> first;
        for(int i = 0; i <size ; i++){
            first.push_back(num[i]);
        }
        result.push_back(first);
        
        while(next_permutation(num.begin(),num.end())){
            vector<int> tmp;
            for(int i = 0; i <size ; i++){
                tmp.push_back(num[i]);
            }
            result.push_back(tmp);
            
        }
        return result;
    }
};


[leetcode]

标签:leetcode   算法   

原文地址:http://blog.csdn.net/chenlei0630/article/details/42064111

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