Problem 1: Multiples of 3 and 5
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
意思就是让你算出在1000以下的3或者5的倍数之和。
我的python代码：
print sum(x for x in range(1000) if x%3==0 or x%5==0)
很简单！
原文地址：http://blog.csdn.net/hackingwu/article/details/26491909
