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ZigZag Conversion
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
创建nRows个数组，将s按照0,1,2,...,nRows-2,nRows-1,nRows-2,...,2,1,0的顺序，
将s中每个字符装入数组。
再依次输出0~nRows-1个数组。
class Solution { public: string convert(string s, int nRows) { if(s == "") return ""; if(nRows == 1) return s; vector<vector<char> > v(nRows); int tag = 1; //1-increase; -1 decrease int ind = -1; for(int i = 0; i < s.size(); i ++) { if(tag == 1) ind ++; else ind --; v[ind].push_back(s[i]); if(ind == 0) tag = 1; else if(ind == nRows-1) //nRows != 1 tag = -1; } string ret; for(int i = 0; i < nRows; i ++) { for(int j = 0; j < v[i].size(); j ++) ret += v[i][j]; } return ret; } };
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原文地址：http://www.cnblogs.com/ganganloveu/p/4179226.html
