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LeetCode:Container With Most Water

时间:2014-12-25 11:24:50      阅读:163      评论:0      收藏:0      [点我收藏+]

标签:algorithm   leetcode   

题目描述:

Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.


代码:

int Solution::maxArea(vector<int> &height)
{
    int low = 0;
    int high = height.size()-1;
    int max_area = (high - low)*min(height[low],height[high]);
    while(low < high)
    {
        max_area = max(max_area,(high - low)*min(height[low],height[high]));
        if(height[low] < height[high])
            low++;
        else
            high--;
    }
    return max_area;
}


LeetCode:Container With Most Water

标签:algorithm   leetcode   

原文地址:http://blog.csdn.net/yao_wust/article/details/42142729

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