标签:
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
1 class Solution { 2 public: 3 int threeSumClosest(vector<int> &num, int target) { 4 5 int n=num.size(); 6 sort(num.begin(),num.end()); 7 8 int i,j,k; 9 int a,b,c; 10 int result; 11 int distance=INT_MAX; 12 13 for(i=0;i<n-2;i++) 14 { 15 j=i+1; 16 k=n-1; 17 18 while(j<k) 19 { 20 a=num[i]; 21 if(i>0&&num[i]==num[i-1]) 22 { 23 break; 24 } 25 b=num[j]; 26 if(j>i+1&&num[j]==num[j-1]) 27 { 28 j++; 29 continue; 30 } 31 32 c=num[k]; 33 if(k<n-1&&num[k]==num[k+1]) 34 { 35 k--; 36 continue; 37 } 38 39 if(a+b+c==target) 40 { 41 return target; 42 } 43 else if(a+b+c<target) 44 { 45 if(target-(a+b+c)<distance) 46 { 47 result=a+b+c; 48 distance=target-result; 49 } 50 j++; 51 } 52 else if(a+b+c>target) 53 { 54 if((a+b+c)-target<distance) 55 { 56 result=a+b+c; 57 distance=result-target; 58 } 59 k--; 60 } 61 } 62 } 63 64 return result; 65 66 67 } 68 };
标签:
原文地址:http://www.cnblogs.com/reachteam/p/4190351.html